Skip to main content

Dog saves fawn from drowning in Virginia lake

dog saves fawn from drowning
(Image credit: Ralph Dorn / Facebook)

A heroic dog has saved a fawn from drowning after he spotted the tiny hoofed mammal stranded and in distress in the middle of a lake, 200 feet from the shore.  

Goldendoodle, Harley, has stolen the hearts of animal-lovers around the world after this special dog risked his own life to rescue a baby deer earlier this month.

Harley’s owner, 62-year-old Ralph Dorn of Culpeper, Virginia, shared this incredible story on Facebook, explaining how he had struggled to find his beloved four-legged-friend one evening. That was until he looked out onto the lake behind his house.

“He was near the middle of the lake herding a little fawn back to the shore line”, said Ralph. “Not sure how the fawn got out there but Harley obviously didn’t ask why, he just jumped into action.”

dog saves fawn from drowning

(Image credit: Ralph Dorn / Facebook)

Once Harley had helped the fawn – thought to have only been a few days old – reach the lake’s edge and Ralph had scooped the baby out onto the ledge, the caring canine instantly began licking the tiny creature.

“Harley didn’t want to leave the fawn”, explained Ralph, as he continued to interact with and care for the fragile little baby.

However, not long after the pair had reached the safety of dry land, the fawn’s mother appeared. It wasn’t until Ralph and Harley had gone inside that the doe approached with caution to collect her baby.

“We could tell right away, even as a puppy, [Harley] had such a good heart,” Ralph said lovingly. “He has always been like that with children and animals. He loves them all.”

Watch the heart-warming moment the deer made it to shore below.

Chloe Petrylak

Chloe is a freelance writer, editor, and proofreader, who has more than eight years experience in media. With a passion for creating content all about wildlife and the environment, she can be found at or @ChloeMayWrites on social media.